Monday, 1 December 2014

PROBLEM SOLVING: FOLDING

Folding Problem: If you fold a strip of paper, by folding the left side on top of the right, over and over again, can you predict the up/down creases after each fold?

Understand the Problem:
- After each fold, there will be a crease that will either point up or down after unfolding the strip.
- The number of creases increase after each fold.

Devise a Plan:
- Fold a strip of paper 4 times while recording the up/down sequence after each fold.

Carry Out the Plan:
Number of Folds (n)
Up/Down Sequence (U = up, D = down)
1
D
2
UDD
3
UUDDUDD
4
UUDUUDDDUUDDUDD

Look Back:
- At first, I found that the number of creases for the successive fold would be ((2^n - 2^(n-1)) + the number of creases previously)
- Then I noticed that this equation related to the sequence: the sequence of one fold was always at the end of the next fold
- To get the overall sequence, however, I noticed that if you started from the left of the sequence with a U, then alternate D/U in between each crease of the original sequence, you would get the next sequence
- e.g. (Bold = crease from original sequence)
         Fold 1 = D = D
         Fold 2 = U + D + D = UDD
         Fold 3 = U + U + D + D + U + D + D = UUDDUDD

Acknowledging Conflicts:
- When trying to find a pattern after each fold, my expectations were always crushed. After 2 folds, I thought a pattern would have been established (ie UDDUDD after 3 folds)
- After I found the equation for the number of creases and realizing the ends of each sequence, I thought I would be able to find the entire sequence, but I only got the last sections
- I knew that there was a pattern involved, so I assumed that if I found an equation, I would be able to guess the next sequence. So, I spent the majority of the time trying to find an equation when I realized that equations only apply to numerical patterns, not directions.
        

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